42 lines
1023 B
C
42 lines
1023 B
C
#include <string.h>
|
|
|
|
/*
|
|
** The strcpy() function copies the string pointed to by src, including the
|
|
** terminating null byte ('\0'), to the buffer pointed to by dest.
|
|
** The strings may not overlap, and the destination string dest must be
|
|
** large enough to receive the copy. Beware of buffer overruns!
|
|
**
|
|
** TODO: use quad-word access and/or DMA !
|
|
** TODO: look at the DSP ?
|
|
*/
|
|
char *strcpy(char *dest, char const *src)
|
|
{
|
|
size_t i;
|
|
|
|
if (src == NULL || dest == NULL)
|
|
return (0);
|
|
i = -1;
|
|
while (src[++i] != '\0')
|
|
dest[i] = src[i];
|
|
dest[i] = '\0';
|
|
return (dest);
|
|
}
|
|
|
|
/*
|
|
** The strncpy() function is similar, except that at most n bytes of src are
|
|
** copied. Warning: If there is no null byte among the first n bytes of src, the
|
|
** string placed in dest will not be null-terminated.
|
|
*/
|
|
char *strncpy(char *dest, char const *str, size_t size)
|
|
{
|
|
size_t i;
|
|
|
|
if (str == NULL || dest == NULL)
|
|
return (0);
|
|
i = -1;
|
|
while (++i < size && str[i] != '\0')
|
|
dest[i] = str[i];
|
|
dest[i] = '\0';
|
|
return (dest);
|
|
}
|